If it's not what You are looking for type in the equation solver your own equation and let us solve it.
=29Y^2-59Y
We move all terms to the left:
-(29Y^2-59Y)=0
We get rid of parentheses
-29Y^2+59Y=0
a = -29; b = 59; c = 0;
Δ = b2-4ac
Δ = 592-4·(-29)·0
Δ = 3481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3481}=59$$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(59)-59}{2*-29}=\frac{-118}{-58} =2+1/29 $$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(59)+59}{2*-29}=\frac{0}{-58} =0 $
| 1/7n=1/3 | | -2-3n-5=-16 | | B=55+(10+9)w | | 4=u+14/5 | | 6m−8=2+9m−1 | | 38=z/5+29 | | b/8+53=61 | | v3– 2= 5 | | 3x+3-x=7+2x | | 2(x-5)+x+5=13 | | v/3–2=5 | | 16v-9v=8 | | 29=x/3+5 | | t/7+18=24 | | 3x+2=2x+0 | | 12.15=2g+3.71 | | t/7+ 18= 24 | | -3(2x-2)=0 | | 1.62g-7=0.29 | | (x-4)-(x+3)=9x | | Y/3+8y/4=y+7/2 | | 2.5j+5=1.5+1.5j | | Y/3+8y/4=y+7- | | 6(y-7)=8y-42 | | 2+3x=17-2x | | 12x-3x+99=12x+57 | | 4x+6=5(x-4) | | Y/3+8y/4=y+4 | | 2x+(4+3x)/5=2-(x-6)/10 | | 6x-8+6x+6=4x+8x-5 | | -8(-4-7x)+6=430 | | 203=102-w |